- III only
- I and III only
- II and III only
- I, II, and III
Show answer and solution
Solution walkthrough
- Since the average time for the 10 members of team A is 3.41 minutes, the sum of the 10 times for team A is equal to minutes. Since the average time for the 10 members of team B is 3.79 minutes, the sum of the 10 times for team B is equal to minutes.
- Since the sum of the 10 times for team B is greater than the sum of the 10 times for team A, it must be true that at least one of the times for team B must be greater than one of the times for team A. Thus, statement III is true.
- However, it’s possible that at least some of the times for team A were greater than some of the times for team B. For example, all of team A’s times could be 3.41 minutes, and team B could have 1 time of 3.34 minutes and 9 times of 3.84 minutes.
- Thus, statement I need not be true. It’s also possible that the median of the times for team B is less than the median of the times for team A.
- For example, all of team A’s times could be 3.41 minutes, and team B could have 6 times of 3.37 minutes and 4 times of 4.42 minutes; then the median of team B’s times would be 3.37 minutes and the median of team A’s times would be 3.41 minutes. Thus, statement II need not be true.